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arr[k++] = leftArr[i++];，详情可参考91视频
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思路：① 找初始左边界：第一个 nums[i] nums[i+1]；② 找初始右边界：最后一个 nums[i] < nums[i-1]；③ 求 [left,right] 内 min、max；④ 向左扩展：nums[left-1] minVal 则 left--；⑤ 向右扩展：nums[right+1] < maxVal 则 right++。长度 = right - left + 1。。业内人士推荐爱思助手下载最新版本作为进阶阅读
Moment officers rescue injured bald eagle from icy Hudson River
In a live demo, Gore walked through how a new developer with no prior credentials spins up an identity, joins a Linux Foundation community, and then establishes a relationship with another participant using pairwise DIDs. Once that relationship exists, the two sides can exchange richer, verifiable relationship credentials (VRCs) that record facts such as when the relationship started, the level of trust it reflects, and how long the credential should remain valid.